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[Xen-devel] Question about the credit2 sources in xen-unstable tree.

To: George Dunlap <George.Dunlap@xxxxxxxxxxxxx>, xen devel <xen-devel@xxxxxxxxxxxxxxxxxxx>
Subject: [Xen-devel] Question about the credit2 sources in xen-unstable tree.
From: peb1611 <peb1611@xxxxxxxxx>
Date: Tue, 05 Apr 2011 17:17:26 +0900
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Hi, all

I am analyzing the credit2 scheduler in order to adopt to my own private
cloud, which should satisfy the conditions of some latency sensitive
applications.

In the latest xen-unstable repository, which is tip tags, I found some
codes that is not understandable to me.

In the xen/common/sched_credit2.c,

/* How long should we let this vcpu run for? */
static s_time_t
csched_runtime(const struct scheduler *ops, int cpu, struct csched_vcpu
*snext)
{
s_time_t time = CSCHED_MAX_TIMER;
struct csched_runqueue_data *rqd = RQD(ops, cpu);
struct list_head *runq = &rqd->runq;

if ( is_idle_vcpu(snext->vcpu) )
return CSCHED_MAX_TIMER;

/* Basic time */
time = c2t(rqd, snext->credit, snext);

/* Next guy on runqueue */
if ( ! list_empty(runq) )
{
struct csched_vcpu *svc = __runq_elem(runq->next);
s_time_t ntime;

if ( ! is_idle_vcpu(svc->vcpu) )
{
ntime = c2t(rqd, snext->credit - svc->credit, snext);

if ( time > ntime )
time = ntime;
}
}

/* Check limits */
if ( time < CSCHED_MIN_TIMER )
time = CSCHED_MIN_TIMER;
else if ( time > CSCHED_MAX_TIMER )
time = CSCHED_MAX_TIMER;

return time;
}

As I understand, this function is used to determining the next vcpu's
running time-slice from now to the next scheduling event.

So, what does this code mean?

if ( time > ntime )
time = ntime;

actually, I think it is not different as

if ( svc->credit > 0 )
time = ntime;

If so, It means that if credits of the next guy on runqueue are not
negative caculated time-slice is snext's time, or time of the next guy
is selected and then eventually saturated by the CSCHED_MIN_TIMER.

what is the implication of it?

Am I correct ? If not, would you please kindly let me know about the
mecahnism of caculating the next-time slice?

Thanks

-- 
Eunbyung Park


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