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xen-devel
Re: [Xen-devel] [PATCH RFC 03/12] x86/ticketlock: Use C for __ticket_spi
> --- a/arch/x86/include/asm/spinlock.h
> +++ b/arch/x86/include/asm/spinlock.h
> @@ -33,9 +33,23 @@
> * On PPro SMP or if we are using OOSTORE, we use a locked operation to
> unlock
> * (PPro errata 66, 92)
> */
> -# define UNLOCK_LOCK_PREFIX LOCK_PREFIX
> +static __always_inline void __ticket_unlock_release(struct arch_spinlock
> *lock)
> +{
> + if (sizeof(lock->tickets.head) == sizeof(u8))
> + asm (LOCK_PREFIX "incb %0"
> + : "+m" (lock->tickets.head) : : "memory");
> + else
> + asm (LOCK_PREFIX "incw %0"
> + : "+m" (lock->tickets.head) : : "memory");
Should those be 'asm volatile' to make them barriers as well? Or do we
not have to worry about that on a Pentium Pro SMP?
> +
> +}
> #else
> -# define UNLOCK_LOCK_PREFIX
> +static __always_inline void __ticket_unlock_release(struct arch_spinlock
> *lock)
> +{
> + barrier();
> + lock->tickets.head++;
> + barrier();
> +}
Got a question:
This extra barrier() (which I see gets removed in git tree) was
done b/c the function is inlined and hence the second barrier() inhibits
gcc from re-ordering __ticket_spin_unlock instructions? Which is a big
pre-requisite in patch 7 where this function expands to:
static __always_inline void __ticket_spin_unlock(arch_spinlock_t *lock)
{
__ticket_t next = lock->tickets.head + 1; // This code
is executed before the lock->tickets.head++ b/c of the 1st barrier?
Or would it be done irregardless b/c gcc sees the data dependency here?
__ticket_unlock_release(lock); <- expands to
"barrier();lock->tickets.head++;barrier()"
+ __ticket_unlock_kick(lock, next); <- so now the second barrier()
affects this code, so it won't re-order the lock->tickets.head++ to be called
after this function?
This barrier ("asm volatile("" : : : "memory")); from what I've been reading
says : "Don't re-order the instructions within this scope and starting
right below me." ? Or is it is just within the full scope of the
function/code logic irregardless of the 'inline' defined in one of them?
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