Re: [Xen-API] Simple Java API example

[Christian Smith <Christian.Smith@xxxxxxx>]

Thanks for that Stefan, just what I was looking for :-)

Cheers,
Christian


Stefan Berger wrote:
> *This program should show all VMs' UUIDs.*
>
> *I added the line*
>
> *(xen-api-server (( 0.0.0.0:9363 none )))*
>
> *to /etc/xen/xend-config.sxp before starting xend.*
>
> *   Stefan*
>
>
> *package* test;
>
> *import* java.net.MalformedURLException;
> *import* java.net.URL;
> *import* java.util.HashMap;
> *import* org.apache.xmlrpc.XmlRpcException;
> *import* org.apache.xmlrpc.client.XmlRpcClient;
> *import* org.apache.xmlrpc.client.XmlRpcClientConfigImpl;
>
> *public* *class* Test {
>         *private* *static* XmlRpcClientConfigImpl /config/;
>         *private* *static* XmlRpcClient /client/;        
>
>         /**
>          * *@param* args
>          */
>         *public* *static* *void* main(String[] args) {
>                 URL url = *null*;
>                 *try* {
>                         url = *new* 
> URL("http://your.xen.machine.ip.address:9363";);
>                 } *catch* (MalformedURLException e) {
>                         System./out/.println("Malformed URL?");
>                         System./exit/(-1);
>                 }
>                 /config/ = *new* XmlRpcClientConfigImpl();
>             /config/.setServerURL(url);
>             /client/ = *new* XmlRpcClient();
>             /client/.setConfig(/config/);
>             String username = "any";
>             String password = "any";
>             Object[] params = *new* Object[]{username, password};
>                 HashMap<String, String> result = *null*;
>                 *try* {
>                         result = (HashMap) 
> /client/.execute("session.login_with_password", params);
>                 } *catch* (XmlRpcException e) {
>                         System./out/.println("Could not open session");
>                         System./exit/(-1);
>                 }
>                 String status = result.get("Status");
>                 *if* (status.compareTo("Success") == 0) {
>                         String uuid = result.get("Value");
>                     params = *new* Object[]{uuid};
>                         *try* {
>                                 result = (HashMap) 
> /client/.execute("VM.get_all", params);
>                         } *catch* (XmlRpcException e) {
>                                 System./out/.println("Could not get 
> VMs' UUIDs");
>                                 System./exit/(-1);
>                         }
>                         Object res = result.get("Value");
>                         *if* (res.getClass() == Object[].*class*) {
>                                 Object[] arr = (Object[])res;
>                                 *int* i;
>                                 *for* (i = 0; i < arr.length; i++) {
>                                         System./out/.println("VM UUID: 
> " +(String)arr[i]);
>                                 }
>                         }
>                        
>                 }
>         }
> }
>
> xen-api-bounces@xxxxxxxxxxxxxxxxxxx wrote on 04/05/2007 08:10:10 AM:
>
> > Hi All,
> >
> > I am trying to talk to the Xen API with Java and
> > 'org.apache.xmlrpc.client.XmlRpcClient' (version 3).  I was 
> wondering if
> > someone could give me a very short example of connecting to the server
> > and getting a list of VM's?  I have never used XML-RPC before and the
> > tutorials ive found dont seem to apply to this version of the xmlrpc 
> api.
> >
> > Thanks in advance,
> > Christian
> >
> > _______________________________________________
> > xen-api mailing list
> > xen-api@xxxxxxxxxxxxxxxxxxx
> > http://lists.xensource.com/cgi-bin/mailman/listinfo/xen-api
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